A cylinder holds whatever its circular base sweeps out as it rises to full height, so its volume is the base area times the height. For a right circular cylinder with radius rr and height hh,

V=πr2hV = \pi r^2 h

In this formula rr is the radius of the base, πr2\pi r^2 is the area of that circular base, and hh is the perpendicular height between the two circular faces. If a problem gives the diameter dd instead, convert first with r=d2r = \frac{d}{2}.

Why The Formula Holds

The reasoning is short: a cylinder is a prism with a circular base, and any prism has volume equal to base area times height. The base area of a circle is πr2\pi r^2, so

V=(πr2)h=πr2hV = (\pi r^2)h = \pi r^2 h

That also explains why the radius is squared while the height is not. The r2r^2 comes straight from the circle's area; the height is multiplied only once as the base is stacked upward. The practical consequence: if the height doubles, the volume doubles, but if the radius doubles, the volume becomes four times as large because the base area depends on r2r^2.

Worked Example: Radius 44 cm, Height 1010 cm

Start with the formula:

V=πr2hV = \pi r^2 h

Substitute r=4r = 4 and h=10h = 10:

V=π(4)2(10)V = \pi (4)^2(10)

Square the radius first, then multiply:

V=π(16)(10)=160πV = \pi (16)(10) = 160\pi

So the exact volume is 160π cm3160\pi\ \text{cm}^3. If a decimal is required, use π3.14159\pi \approx 3.14159:

V502.7 cm3V \approx 502.7\ \text{cm}^3

Many classes prefer the exact form 160π cm3160\pi\ \text{cm}^3 unless the instructions ask you to round.

Practice It Yourself

First, redo the example when it is described with diameter 88 cm and height 1010 cm. The radius is half the diameter, so r=4r = 4 cm, and

V=π(4)2(10)=160π cm3V = \pi (4)^2(10) = 160\pi\ \text{cm}^3

Same cylinder, same answer, because the formula always uses the radius.

Next, try radius 66 cm and height 33 cm. Set it up before calculating:

V=π(6)2(3)V = \pi (6)^2(3)

If you get 108π cm3108\pi\ \text{cm}^3, your setup is consistent.

Calculation Traps To Watch For

  1. Using the diameter directly in V=πr2hV = \pi r^2 h. Convert to radius first.
  2. Forgetting to square the radius. The formula uses r2r^2, not 2r2r.
  3. Multiplying by the slanted side of an oblique drawing instead of the perpendicular height. The formula needs the actual height between the bases.
  4. Writing square units instead of cubic units. Volume should be in units such as cm3\text{cm}^3, m3\text{m}^3, or in3\text{in}^3.
  5. Rounding too early when the problem allows an exact answer in terms of π\pi.

One more condition to keep in mind: this formula gives the outer volume of a hollow cylinder unless you subtract the empty inner part, and if the radius changes along the height, the shape is not a cylinder, so the formula does not apply directly. Cans, pipes, tanks, candles, and circular columns are the usual fits.

A Clean Next Step

If you want to see exactly where the πr2\pi r^2 part comes from, compare this formula with the area of a circle. The cylinder formula is just that circle, given height.

Frequently Asked Questions

How do you find the volume of a cylinder?
Multiply the area of the circular base by the height. The base area is pi times the radius squared, so the volume equals pi times radius squared times height. For example, a cylinder with radius 4 cm and height 10 cm has volume 160 pi cubic centimeters, about 502.7 cubic centimeters.
What do you do if a cylinder problem gives the diameter instead of the radius?
Convert first: the radius is half the diameter. A cylinder described with diameter 8 cm has radius 4 cm, and that radius goes into the formula. Plugging the diameter directly into the formula is one of the most common errors on homework and tests.
What happens to a cylinder's volume if you double the radius?
The volume becomes four times as large, because the base area depends on the radius squared. Doubling the height, by contrast, only doubles the volume, since height is multiplied once. This difference comes straight from how radius and height appear in the formula.
Should a cylinder volume answer be left in terms of pi or rounded?
Many classes prefer the exact form, such as 160 pi cubic centimeters, unless the instructions ask for a decimal. If a decimal is required, multiply by an approximation of pi at the end. Rounding too early when an exact answer is allowed is a common mistake.
When does the cylinder volume formula not apply?
It applies when an object can be modeled as a cylinder, like cans, pipes, tanks, or columns. If the radius changes along the height, the shape is not a cylinder, so the formula does not apply directly. For hollow objects, it gives the outer volume unless you subtract the empty inner part.

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