A sequence is a list; a series is the sum of that list. For arithmetic patterns, that one distinction decides which formula you reach for — the term formula or the sum formula.

An arithmetic sequence changes by the same amount each step (the common difference dd), and an arithmetic series is the sum of its terms. With first term a1a_1 and common difference dd:

an=a1+(n1)dSn=n2(a1+an)a_n = a_1 + (n - 1)d \qquad S_n = \frac{n}{2}(a_1 + a_n)

Sequence vs. series, side by side

                  Arithmetic sequence        Arithmetic series
Question asked    "What is a term?"          "What is the total?"
Object            ordered list itself        sum of the list's terms
Formula           a_n = a_1 + (n-1)d         S_n = (n/2)(a_1 + a_n)
Example: 2,5,8,11 the list 2, 5, 8, 11       2 + 5 + 8 + 11 = 26

A sequence is arithmetic only if the difference between consecutive terms stays constant. For instance, 4,7,10,13,164, 7, 10, 13, 16 is arithmetic because each term increases by 33, so d=3d = 3. By contrast 5,9,14,205, 9, 14, 20 is not, because the differences are 44, 55, and 66; since the difference changes, the arithmetic formulas do not apply.

When to use which

Use the term formula an=a1+(n1)da_n = a_1 + (n-1)d when a question asks for a particular term, such as the 2020th value. Use the sum formula Sn=n2(a1+an)S_n = \frac{n}{2}(a_1 + a_n) when a question asks for the total of the first nn terms; if you do not yet know the last term ana_n, find it first with the term formula. Both require a constant common difference.

Worked example: the 2020th term and the first 2020-term sum

Consider the sequence

5,8,11,14,17,5, 8, 11, 14, 17, \ldots

so a1=5a_1 = 5 and d=3d = 3.

Find the 2020th term with the term formula:

a20=5+(201)(3)=5+57=62a_{20} = 5 + (20 - 1)(3) = 5 + 57 = 62

Find the sum of the first 2020 terms with the sum formula, using a20=62a_{20} = 62:

S20=202(5+62)=1067=670S_{20} = \frac{20}{2}(5 + 62) = 10 \cdot 67 = 670

So the 2020th term is 6262 and the sum of the first 2020 terms is 670670. The sum formula works because the first and last terms have the same average as the second and second-to-last, and so on inward; the total is therefore the number of terms times the average of the first and last term.

Common confusions and how to keep them straight

  • Mixing up nn and dd. nn counts the position or number of terms; dd is the constant difference. Different jobs.
  • Forgetting the (n1)(n-1). The term formula is an=a1+(n1)da_n = a_1 + (n-1)d, not a1+nda_1 + nd, because there are only n1n-1 jumps from the first term to the nnth.
  • Using the sum formula on a non-arithmetic list. If the differences are not constant, the arithmetic series formula does not apply — check the pattern first.
  • Losing the sign of the difference. A decreasing sequence has negative dd: in 12,9,6,312, 9, 6, 3, the common difference is 3-3, not 33.

When arithmetic sequences and series are used

They appear whenever a quantity changes by a constant amount each step: saving the same amount monthly, rows of seats that grow by a fixed number, algebra problems built on linear growth. They fit additive change. If each step multiplies by the same factor instead of adding the same amount, you have a geometric sequence instead.

To compare the two ideas directly, take 18,15,12,9,18, 15, 12, 9, \ldots and find the common difference, the 1212th term, and the sum of the first 1212 terms. Then solve the same kind of problem for a geometric sequence and notice what changes when the pattern is constant multiplication rather than constant addition.

Frequently Asked Questions

What is the difference between an arithmetic sequence and an arithmetic series?
An arithmetic sequence is the ordered list of terms itself, while an arithmetic series is the sum of those terms. For 2, 5, 8, 11, the sequence is the list, and the corresponding series is 2 plus 5 plus 8 plus 11, which equals 26. One question asks for a term, the other for a total.
How do you find the nth term of an arithmetic sequence?
Use the formula a sub n equals a sub 1 plus n minus 1 times d, where a sub 1 is the first term and d is the common difference. For the sequence 5, 8, 11, 14 with d equal to 3, the 20th term is 5 plus 19 times 3, which equals 62.
How do you find the sum of the first n terms of an arithmetic sequence?
Use S sub n equals n over 2 times the quantity a sub 1 plus a sub n. If you do not know the last term yet, find it first with the nth term formula. For the sequence starting at 5 with difference 3, the sum of the first 20 terms is 10 times 67, which equals 670.
How do you know if a sequence is arithmetic?
Check that the difference between consecutive terms stays constant. The sequence 4, 7, 10, 13, 16 is arithmetic because each term increases by 3. The sequence 5, 9, 14, 20 is not, because the differences are 4, 5, and 6, so the arithmetic formulas do not apply to it.
Why is the nth term formula a1 plus n minus 1 times d and not a1 plus nd?
Because there are only n minus 1 jumps from the first term to the nth term. Counting from the first term, you add the common difference once to reach the second term, twice to reach the third, and so on, so reaching position n takes n minus 1 additions of d.

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