The volume of a cone is the amount of space inside it. For a cone with base radius rr and perpendicular height hh, use

V=13πr2hV = \frac{1}{3}\pi r^2 h

The base area is πr2\pi r^2, so this formula is really saying:

cone volume=13(base area)(height)\text{cone volume} = \frac{1}{3}(\text{base area})(\text{height})

If the base is circular, that becomes 13πr2h\frac{1}{3}\pi r^2 h.

What the formula means

The factor πr2\pi r^2 is the area of the circular base. Multiplying by hh would give the volume of a cylinder with the same base and height.

A cone is more tapered, so it holds less than that cylinder. In fact, with the same base area and height, it holds exactly one-third as much.

That gives the fastest intuition for the formula:

Vcone=13Vcylinder=13πr2hV_{\text{cone}} = \frac{1}{3}V_{\text{cylinder}} = \frac{1}{3}\pi r^2 h

Why the one-third appears

One standard derivation uses cross-sections. Measure height xx upward from the tip of the cone. At that level, the radius scales linearly, so

radius at height x=rhx\text{radius at height } x = \frac{r}{h}x

The cross-sectional area there is

A(x)=π(rhx)2A(x) = \pi \left(\frac{r}{h}x\right)^2

Add those thin circular slices from x=0x = 0 to x=hx = h:

V=0hπ(rhx)2dxV = \int_0^h \pi \left(\frac{r}{h}x\right)^2 dx V=πr2h20hx2dx=πr2h2(h33)=13πr2hV = \frac{\pi r^2}{h^2}\int_0^h x^2 dx = \frac{\pi r^2}{h^2}\left(\frac{h^3}{3}\right) = \frac{1}{3}\pi r^2 h

If you have not studied calculus yet, the practical takeaway is still simple: a cone with the same base and height as a cylinder has one-third the volume.

One worked example

Suppose a cone has radius 33 cm and height 88 cm.

Start with the formula:

V=13πr2hV = \frac{1}{3}\pi r^2 h

Substitute r=3r = 3 and h=8h = 8:

V=13π(32)(8)V = \frac{1}{3}\pi (3^2)(8)

Square the radius and simplify:

V=13π(9)(8)=24πV = \frac{1}{3}\pi (9)(8) = 24\pi

So the exact volume is

24π cm324\pi\ \text{cm}^3

If you need a decimal approximation,

24π75.4 cm324\pi \approx 75.4\ \text{cm}^3

Common mistakes

  1. Using the diameter as if it were the radius. If the diameter is 66 cm, the radius is 33 cm.
  2. Using slant height instead of perpendicular height. The volume formula needs the straight height from base to tip.
  3. Forgetting the one-third factor. πr2h\pi r^2 h is the cylinder formula, not the cone formula.
  4. Forgetting to square the radius. The formula uses r2r^2, not rr.
  5. Dropping cubic units. Volume should be written in units such as cm3\text{cm}^3 or m3\text{m}^3.

When the formula is used

This formula is used in geometry, engineering estimates, packaging, and any problem where a shape can be modeled as a cone or near-cone. Common examples include funnels, piles of material, and conical tanks.

If the object is only approximately conical, the result is also an approximation. The closer the shape is to a true cone, the more useful the estimate will be.

A quick check that catches errors

If a cone and a cylinder have the same base radius and the same height, the cone's volume should be smaller by a factor of 33.

So if your cone answer comes out equal to πr2h\pi r^2 h, you have probably missed the 13\frac{1}{3}.

Try your own version

Try your own version with radius 55 and height 1212. Before calculating, predict whether the exact answer should be larger or smaller than the cylinder volume with the same dimensions. If you want to compare a few cases quickly, solve a similar problem with GPAI Solver.

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