Reach for the cone volume formula whenever an object narrows from a circular base to a single point: funnels, piles of sand, paper cups, conical tanks. As long as the shape is a true cone or close to one, the same procedure gives the space inside it. For base radius rr and perpendicular height hh,

V=13πr2hV = \frac{1}{3}\pi r^2 h

Since the base area is πr2\pi r^2, the formula is really saying

cone volume=13(base area)(height)\text{cone volume} = \frac{1}{3}(\text{base area})(\text{height})

The Procedure, Step By Step

  1. Identify the base radius rr. If you are given the diameter, divide by 22 first.
  2. Identify the perpendicular height hh, measured straight from base to tip, not the slant height.
  3. Substitute into V=13πr2hV = \frac{1}{3}\pi r^2 h, squaring the radius before multiplying.
  4. Keep the units consistent so the final volume comes out in cubic units.
  5. Decide on exact or decimal form, leaving the answer in terms of π\pi unless a decimal is requested.

Why The One-Third Is There

Multiplying base area πr2\pi r^2 by height hh alone would give the volume of a cylinder with the same base and height. A cone is more tapered, so it holds less, exactly one-third as much:

Vcone=13Vcylinder=13πr2hV_{\text{cone}} = \frac{1}{3}V_{\text{cylinder}} = \frac{1}{3}\pi r^2 h

One standard derivation makes that precise with cross-sections. Measure height xx upward from the tip; the radius scales linearly, so

radius at height x=rhx\text{radius at height } x = \frac{r}{h}x

The cross-sectional area there is

A(x)=π(rhx)2A(x) = \pi \left(\frac{r}{h}x\right)^2

Adding those thin slices from x=0x = 0 to x=hx = h,

V=0hπ(rhx)2dx=πr2h2(h33)=13πr2hV = \int_0^h \pi \left(\frac{r}{h}x\right)^2 dx = \frac{\pi r^2}{h^2}\left(\frac{h^3}{3}\right) = \frac{1}{3}\pi r^2 h

If you have not studied calculus yet, the practical takeaway still holds: a cone with the same base and height as a cylinder has one-third the volume.

A Worked Run Through The Steps

Take a cone with radius 33 cm and height 88 cm.

The radius is r=3r = 3 and the perpendicular height is h=8h = 8. Substitute:

V=13π(32)(8)V = \frac{1}{3}\pi (3^2)(8)

Square the radius and simplify:

V=13π(9)(8)=24πV = \frac{1}{3}\pi (9)(8) = 24\pi

So the exact volume is

24π cm324\pi\ \text{cm}^3

and as a decimal,

24π75.4 cm324\pi \approx 75.4\ \text{cm}^3

Where Each Step Goes Wrong, And How To Catch It

  • Reading the radius: using the diameter as if it were the radius. A diameter of 66 cm means a radius of 33 cm.
  • Reading the height: using slant height instead of the perpendicular height from base to tip.
  • Substituting: forgetting to square the radius. The formula uses r2r^2, not rr.
  • Substituting: dropping the one-third. Note that πr2h\pi r^2 h is the cylinder formula, not the cone formula.
  • Labeling: leaving off cubic units such as cm3\text{cm}^3 or m3\text{m}^3.

A self-check that catches most of these: a cone and cylinder with the same radius and height differ by a factor of 33. If your cone answer comes out equal to πr2h\pi r^2 h, you have probably missed the 13\frac{1}{3}. And remember the model condition: if the object is only approximately conical, the result is also an approximation.

Run It Yourself

Work the same five steps for radius 55 and height 1212. Before calculating, predict whether the exact answer should be larger or smaller than the cylinder volume with the same dimensions. To compare several cases quickly, solve a similar problem with GPAI Solver.

Frequently Asked Questions

What is the volume formula for a cone?
For a cone with base radius $r$ and perpendicular height $h$, the volume is $V = \frac{1}{3}\pi r^2 h$.
Why is there a one-third in the cone formula?
A cone with the same base area and height as a cylinder has one-third of the cylinder's volume. One way to justify that result is with cross-sections or integration.
Do you use slant height for cone volume?
No. Volume uses the perpendicular height $h$, not the slant height. Slant height is usually used for surface area.

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