Hess's law explains how to find the enthalpy change of a reaction by adding other reactions with known enthalpy changes. It works because the overall ΔH\Delta H depends on the initial and final states, not on the route between them.

In short: if the chemical equations add up to the target reaction, their enthalpy changes add up too. This is only valid when the equations describe the same substances in the same physical states under the same conditions.

What Hess's law means in chemistry

Imagine taking the same chemical system from one set of reactants to one set of products by two different routes. If the initial and final states are the same, the total enthalpy change is the same as well.

That is why Hess's law is useful in thermochemistry. Some reaction enthalpies are hard to measure directly, but the same overall change can often be built from reactions whose ΔH\Delta H values are already known.

The idea is usually written as

ΔHoverall=ΔH1+ΔH2+ΔH3+\Delta H_{overall} = \Delta H_1 + \Delta H_2 + \Delta H_3 + \cdots

This statement applies only when the adjusted equations really combine to give the target reaction.

How to calculate ΔH\Delta H with Hess's law

Use this sequence:

  1. Write the target reaction exactly.
  2. Pick known reactions that can be rearranged to make it.
  3. Reverse any reaction if needed, and reverse the sign of ΔH\Delta H.
  4. Multiply any reaction if needed, and multiply ΔH\Delta H by the same factor.
  5. Add the equations and cancel species that appear on both sides.

The algebra with the equations and the algebra with ΔH\Delta H must stay matched. If you change one, you must change the other in the same way.

Worked example: finding ΔH\Delta H for forming CO2CO_2

Suppose you want the enthalpy change for

C(graphite)+O2(g)CO2(g)C(graphite) + O_2(g) \rightarrow CO_2(g)

and you know these two reactions:

C(graphite)+12O2(g)CO(g)ΔH=110.5 kJ/molC(graphite) + \frac{1}{2}O_2(g) \rightarrow CO(g) \qquad \Delta H = -110.5\ \mathrm{kJ/mol} CO(g)+12O2(g)CO2(g)ΔH=283.0 kJ/molCO(g) + \frac{1}{2}O_2(g) \rightarrow CO_2(g) \qquad \Delta H = -283.0\ \mathrm{kJ/mol}

Now add them:

C(graphite)+12O2(g)CO(g)CO(g)+12O2(g)CO2(g)\begin{aligned} C(graphite) + \frac{1}{2}O_2(g) &\rightarrow CO(g) \\ CO(g) + \frac{1}{2}O_2(g) &\rightarrow CO_2(g) \end{aligned}

The CO(g)CO(g) cancels because it appears on both sides. The two 12O2(g)\frac{1}{2}O_2(g) terms combine to give O2(g)O_2(g), so the overall reaction becomes

C(graphite)+O2(g)CO2(g)C(graphite) + O_2(g) \rightarrow CO_2(g)

Then add the enthalpy changes:

ΔH=110.5 kJ/mol+(283.0 kJ/mol)=393.5 kJ/mol\Delta H = -110.5\ \mathrm{kJ/mol} + (-283.0\ \mathrm{kJ/mol}) = -393.5\ \mathrm{kJ/mol}

So the enthalpy change for forming CO2(g)CO_2(g) from graphite and oxygen is

ΔH=393.5 kJ/mol\Delta H = -393.5\ \mathrm{kJ/mol}

This is the core pattern of Hess's law. You do not need a new formula each time. You need equations that combine to the target reaction, plus careful sign changes and cancellation.

Why enthalpy can be added this way

Hess's law works because enthalpy is a state function. A state function depends on the state itself, not on how the system got there.

That is the main contrast with a path-dependent quantity. If two routes begin and end at the same states, their total enthalpy change must agree. If that were not true, you could create inconsistent energy cycles.

Common Hess's law mistakes

Forgetting to change the sign when reversing a reaction

If you flip a chemical equation, the corresponding ΔH\Delta H must change sign. A reversed exothermic step becomes endothermic, and vice versa.

Forgetting to scale ΔH\Delta H

If you multiply a reaction by 22, you must also multiply ΔH\Delta H by 22. The enthalpy change scales with the amount of reaction written.

Canceling the wrong species

Only cancel a species if it appears on opposite sides after the equations are arranged. If it appears on the same side in two equations, it does not cancel.

Ignoring physical states

States matter in thermochemistry. H2O(l)H_2O(l) and H2O(g)H_2O(g) are not interchangeable, and using the wrong state can give the wrong target reaction and the wrong enthalpy.

When Hess's law is useful

Hess's law is used when a reaction enthalpy is difficult to measure directly but related reactions are known. It often appears with enthalpies of formation, combustion data, and reaction cycles in introductory chemistry.

It is also a good check on thermochemical reasoning. If the equations do not combine cleanly into the target reaction, the enthalpy sum is not ready yet.

Try a similar thermochemistry problem

Try your own version by starting with a target reaction and three known thermochemical equations, then see whether you need to reverse or scale any of them before adding. If you want a related next step, compare this with enthalpy and entropy so the role of ΔH\Delta H fits into the bigger thermodynamics picture.

Frequently Asked Questions

What is Hess's law?
Hess's law says you can find the enthalpy change of a reaction by adding other reactions with known enthalpy changes. If the chemical equations add up to the target reaction, their enthalpy changes add up too. It works because the overall enthalpy change depends on the initial and final states, not on the route between them.
Why does Hess's law work?
Enthalpy is path independent. If the same chemical system goes from one set of reactants to one set of products by two different routes, the total enthalpy change is identical as long as the initial and final states are the same. This lets chemists build hard-to-measure reaction enthalpies from reactions whose values are already known.
How do you calculate enthalpy change using Hess's law?
Write the target reaction exactly, then pick known reactions that can be rearranged to make it. Reverse a reaction if needed and flip the sign of its enthalpy change, or multiply a reaction and multiply its enthalpy change by the same factor. Finally, add the equations, cancel species appearing on both sides, and add the enthalpy values.
What happens to delta H when you reverse a reaction?
You reverse its sign. The algebra applied to the equations and the algebra applied to the enthalpy changes must stay matched: reversing an equation flips the sign of delta H, and multiplying an equation by a factor multiplies delta H by the same factor. Changing one without the other gives a wrong answer.
How do you find the enthalpy of forming CO2 from graphite using Hess's law?
Add the reaction of graphite with half an oxygen molecule to form carbon monoxide, with delta H of -110.5 kilojoules per mole, to the reaction of carbon monoxide with half an oxygen molecule to form carbon dioxide, with delta H of -283.0. The carbon monoxide cancels, giving the target reaction with delta H equal to -393.5 kilojoules per mole.

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