A box and whisker plot shows the center, spread, and possible skew of a data set in one glance. It is built from the five-number summary: minimum, first quartile Q1Q_1, median, third quartile Q3Q_3, and maximum. If your class or software uses the 1.5×IQR1.5 \times IQR rule, the whiskers may stop at the most extreme non-outlier values instead of the absolute minimum and maximum.

The box runs from Q1Q_1 to Q3Q_3, so it contains the middle 50%50\% of the data. The line inside the box is the median. The whiskers show how far the data extends beyond that middle half.

What a box and whisker plot shows

A box plot helps you answer three quick questions:

  • Where is the middle? Look at the median.
  • How spread out is the middle half? Look at the box width.
  • Are the tails balanced? Compare the two whiskers.

The width of the box is the interquartile range, or IQR=Q3Q1IQR = Q_3 - Q_1. A larger IQRIQR means the middle half of the data is more spread out. If one whisker is much longer than the other, the data may be skewed in that direction.

Many box plots also use the 1.5×IQR1.5 \times IQR rule to mark possible outliers. In that version, the whiskers stop at the most extreme non-outlier values. That is why two correct box plots for the same data can look slightly different if they use different whisker rules.

Worked example from data to box plot

Use the ordered data set

3, 5, 6, 7, 8, 9, 12, 153,\ 5,\ 6,\ 7,\ 8,\ 9,\ 12,\ 15

There are 88 values, so the median is the average of the two middle values:

median=7+82=7.5\text{median} = \frac{7 + 8}{2} = 7.5

Because there is an even number of data points, split the list into two equal halves. The lower half is 3,5,6,73, 5, 6, 7, so

Q1=5+62=5.5Q_1 = \frac{5 + 6}{2} = 5.5

The upper half is 8,9,12,158, 9, 12, 15, so

Q3=9+122=10.5Q_3 = \frac{9 + 12}{2} = 10.5

That gives the five-number summary:

min=3,Q1=5.5,median=7.5,Q3=10.5,max=15\text{min} = 3,\quad Q_1 = 5.5,\quad \text{median} = 7.5,\quad Q_3 = 10.5,\quad \text{max} = 15

Now compute the interquartile range:

IQR=Q3Q1=10.55.5=5IQR = Q_3 - Q_1 = 10.5 - 5.5 = 5

If you use the common 1.5×IQR1.5 \times IQR outlier rule, the fences are

Q11.5(IQR)=5.57.5=2Q_1 - 1.5(IQR) = 5.5 - 7.5 = -2

and

Q3+1.5(IQR)=10.5+7.5=18Q_3 + 1.5(IQR) = 10.5 + 7.5 = 18

All the data values fall between 2-2 and 1818, so there are no possible outliers under that rule. For this data set, the box would run from 5.55.5 to 10.510.5, the median line would be at 7.57.5, and the whiskers would reach 33 and 1515.

How to read a box plot quickly

Start with the median line. That tells you where the center of the data sits.

Then compare the width of the box and the lengths of the whiskers. The box shows where the middle 50%50\% of the values lie, while the whiskers show how far the tails extend beyond that region.

Finally, look for asymmetry. If the median is off-center inside the box, or one whisker is much longer than the other, the distribution may not be balanced around the middle.

Common mistakes with box and whisker plots

One common mistake is reading the edges of the box as the minimum and maximum. They usually represent Q1Q_1 and Q3Q_3, not the endpoints of the full data set.

Another mistake is assuming every box plot uses the same whisker rule. Some whiskers extend to the minimum and maximum. Others stop at the most extreme non-outlier values.

It is also easy to forget that quartiles depend on ordered data. If the values are not sorted first, the quartiles and median will be wrong.

When box plots are useful

Box and whisker plots are useful when you want a fast summary of a distribution instead of a full list of values. They are common in statistics classes, experiment summaries, quality control, and comparisons between groups.

They are especially helpful when outliers or skew matter, because the median and quartiles are usually more stable than the mean by itself.

Try a similar data set

Take a short sorted data set, write its five-number summary, and sketch the box before you worry about outliers. If you want to check your quartiles and median on a similar statistics problem, try your own version in a solver after you set up the ordered list yourself.

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